document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1082972>Question 1082972</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please show me the steps on how to do this problem. I forgot how to do it.<BR>\n" );
document.write( "There are two consecutive numbers, where the sum of the lesser number and three times the greater number is 103. What is the greater number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #696959 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=696959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x equal 1 of the numbers.\r<BR>\n" );
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document.write( "since the number are consecutive, then the next number is x + 1.\r<BR>\n" );
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document.write( "the sum of the smaller number and 3 times the larger number is 103.\r<BR>\n" );
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document.write( "that becomes x + 3 * (x + 1) = 103\r<BR>\n" );
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document.write( "simplify to get x + 3x + 3 = 103\r<BR>\n" );
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document.write( "combine like terms to get 4x + 3 = 103\r<BR>\n" );
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document.write( "subtract 3 from both sides to get 4x = 100\r<BR>\n" );
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document.write( "solve for x to get x = 25.\r<BR>\n" );
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document.write( "the smaller number is 25.<BR>\n" );
document.write( "the larger number is 26.\r<BR>\n" );
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document.write( "the sum of the smaller number and 3 times the larger number is equal to 25 + 3 * 26 which is equal to 25 + 78 which is equal to 103.\r<BR>\n" );
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document.write( "this confirms the solution is correct.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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