document.write( "Question 1082753: In a particular card game, players receive five cards from a standard deck of 52 cards (consisting of the standard four suits, and 13 cards of each suit). Determine each of the following probabilities:
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document.write( "a) The probability of 2 or more red cards using a hypergeometric distribution
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document.write( "b) The probability of 2 or more red cards using a normal approximation. Be sure to check that it is appropriate to use an approximation. \n" );
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Algebra.Com's Answer #696874 by natolino_2017(77)![]() ![]() ![]() You can put this solution on YOUR website! a) P(X=a) = (dCa)((N-d)C(n-a))/(NCn)\r \n" ); document.write( "\n" ); document.write( "in this case: N = 52 (number of total cards) \n" ); document.write( " n = 5 (number of picked cards) \n" ); document.write( " d = 26 (number of working cards)\r \n" ); document.write( "\n" ); document.write( "According to the model, it's easier using the complement of the asked probability.\r \n" ); document.write( "\n" ); document.write( "P() = 1 - (P(x=1) + P(x=0) \n" ); document.write( " \n" ); document.write( " 1 - (26C1)(26C4)/(52C5) - (26C2)(26C3)/(52C5) = 5,251/9,996 = 52.531%\r \n" ); document.write( "\n" ); document.write( "b) First Not that the E(x) = nd/N = 5/2 ( So the expected number of red cards is between of two and three)\r \n" ); document.write( "\n" ); document.write( "and V(x) = (N-n)(N-d)(nd)/(N^2(N-1)) = 235/204 (So the variation expected is aproximated one between every experiment).\r \n" ); document.write( "\n" ); document.write( "As N = 52 > 30 it's fair to use a Normal aproximation.\r \n" ); document.write( "\n" ); document.write( "y is a Normal with u= 2.5 and sigma square = 235/204\r \n" ); document.write( "\n" ); document.write( "P(y>=2) using standardization P(Z >= (2-2.5)/(sqrt(235/204))\r \n" ); document.write( "\n" ); document.write( " P(Z >= -0.46585) using symmetry.\r \n" ); document.write( "\n" ); document.write( " 0.5 + P(0 <= z <= 0.46585) Extrapolating\r \n" ); document.write( "\n" ); document.write( " 0.5 + 0.179 = 0.679 = 67.9%\r \n" ); document.write( "\n" ); document.write( "which is different that the exact value, but the error is less than 30%.\r \n" ); document.write( "\n" ); document.write( "If we were using several deck of cards the error would minor.\r \n" ); document.write( "\n" ); document.write( "@natolino_ \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |