document.write( "Question 1082534: Find the asymptote of a hyperbola with equation 25x^2 - 16y^2 = 400 \n" ); document.write( "
Algebra.Com's Answer #696823 by MathLover1(20850)\"\" \"About 
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Find the asymptote of a hyperbola with equation \"25x%5E2+-+16y%5E2+=+400+\"\r
\n" ); document.write( "\n" ); document.write( " first have to convert this equation to \"conics\" form by completing the square:\r
\n" ); document.write( "\n" ); document.write( "\"25x%5E2+-+16y%5E2+=+400\"\r
\n" ); document.write( "\n" ); document.write( "\"25x%5E2%2F400+-+16y%5E2+%2F400=+400%2F400+\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F16+-+y%5E2+%2F25=+1\"\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "\"%28x-0%29%5E2%2F16-+%28y-0%29%5E2+%2F25=+1\"\r
\n" ); document.write( "\n" ); document.write( "so, \"h=0\" and \"k=0\"\r
\n" ); document.write( "\n" ); document.write( "\"a=4\", \"b=5\"\r
\n" ); document.write( "\n" ); document.write( " the asymptes are then given by the straight-line equations \r
\n" ); document.write( "\n" ); document.write( "\"y=mx\"\r
\n" ); document.write( "\n" ); document.write( "In this case
\n" ); document.write( "\"b=5\"
\n" ); document.write( "\"a=4\"\r
\n" ); document.write( "\n" ); document.write( "So the slopes are \"m=5%2F4\" and \"-5%2F4\", and the asymptes are: \r
\n" ); document.write( "\n" ); document.write( " \"y+=+%285x%29%2F4\" and \"y+=+-%285x%29%2F4\"\r
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