document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1082710>Question 1082710</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If roger has 43 coins consisting of only dimes and quarters and in total he has 6.55$ How many does he have of each coin  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #696803 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=696803\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">   If roger has 43 coins consisting of only dimes and quarters<BR>\n" );
document.write( "d + q = 43<BR>\n" );
document.write( "d = 43 - q; use this form for substitution<BR>\n" );
document.write( " and in total he has 6.55$<BR>\n" );
document.write( ".10d + .25q = 6.55<BR>\n" );
document.write( "Replace d with (43-q)<BR>\n" );
document.write( ".10(43 -q) + .25q = 6.55<BR>\n" );
document.write( "4.3 - .10q + .25q = 6.55<BR>\n" );
document.write( ".15q = 6.55 - 4.30<BR>\n" );
document.write( ".15q = 2.25<BR>\n" );
document.write( "q = 2.25/.15<BR>\n" );
document.write( "q = 15 quarters<BR>\n" );
document.write( " How many does he have of each coin<BR>\n" );
document.write( "I'll let you find the no. of dimes, check the solutions using the 2nd equation  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );