document.write( "Question 1082714: The sum of the digit of the two numbers is 5.if 10 times the tens digit is added to 4 times the unit digit,the number obtained is in the reverse order of the digit of the original number.find the number?
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Algebra.Com's Answer #696801 by ikleyn(52788) $\"\"$ $\"About$

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\n" ); document.write( "The sum of the $\"highlight%28cross%28digit%29%29\"$ digits of the two $\"highlight%28digit%29\"$ $\"highlight%28cross%28numbers%29%29\"$ number is 5.
\n" ); document.write( "If 10 times the tens digit is added to 4 times the unit digit,
\n" ); document.write( "the number obtained is in the reverse order of the $\"highlight%28cross%28digit%29%29\"$ digits of the original number. find the number?
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document.write( "The equations are \r\n" );
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document.write( "t + u = 5,          (1)    (where t is the \"tens\" digit, u is the \"units\" digit.)\r\n" );
document.write( "10t+4u = 10u + t.   (2)\r\n" );
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document.write( "Simplify:\r\n" );
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document.write( "t + u = 5,\r\n" );
document.write( "9t = 6u.\r\n" );
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document.write( "t = 5-u,\r\n" );
document.write( "9*(5-u) = 6u,\r\n" );
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document.write( "45 - 9u = 6u,\r\n" );
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document.write( "45 = 15u  --->  u = 3,  t = 2.\r\n" );
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document.write( "The original number is 23.\r\n" );
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