document.write( "Question 1082720: The following data represent the asking price of a simple random sample of homes for sale. Construct a 99% confidence interval with and without the outlier included. Comment on the effect the outlier has on the confidence interval.\r
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document.write( "$223,000
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document.write( "$279,900
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document.write( "$19,900
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document.write( "$143,000
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document.write( "$205,800
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document.write( "$181,500
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document.write( "$459,900
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document.write( "$212,000
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document.write( "$187,500
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document.write( "$201,500
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document.write( "$147,800
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document.write( "$264,900 \n" );
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Algebra.Com's Answer #696784 by Boreal(15235) You can put this solution on YOUR website! mean with is $210,558 with s=$102,878 \n" ); document.write( "99%CI is ($118,320, $302,800) \n" ); document.write( "without the outlier mean is $227,891 with s=$87,618 \n" ); document.write( "99%CI is ($144,170, $311,620) \n" ); document.write( "This is done using t.995, df=11 * s/sqrt(12) for the first and 1 less in n and df for the second. That is the interval, and it is added to and subtracted from the sample mean. \n" ); document.write( "The interval is narrower, because the variability is less. The mean is larger \n" ); document.write( " because a small number outlier was removed. \n" ); document.write( " |