document.write( "Question 1082672: 2x+2y-z=10
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document.write( "X+y+z=11
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document.write( "2x+y+-z=7
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document.write( "So x,y,and z =? \n" );
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Algebra.Com's Answer #696761 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 2x+2y-z=10 \n" ); document.write( "X+y+z=11 \n" ); document.write( "2x+y+-z=7 \n" ); document.write( "----------- \n" ); document.write( "Since all z terms have a coefficient of 1, I would use elimination. \n" ); document.write( "--- \n" ); document.write( "Add Eqn 1 and 2: \n" ); document.write( "2x+2y-z=10 \n" ); document.write( "X+y+z=11 \n" ); document.write( "------------------- Add \n" ); document.write( "2x + 3y = 21 Eqn A \n" ); document.write( "--- \n" ); document.write( "Add Eqn 2 & 3 \n" ); document.write( "X+y+z=11 \n" ); document.write( "2x+y+-z=7 \n" ); document.write( "-------------- Add \n" ); document.write( "3x + 2y = 18 Eqn B \n" ); document.write( "--- \n" ); document.write( "4x + 6y = 42 Eqn A times 2 \n" ); document.write( "9x + 6y = 54 Eqn B times 3 \n" ); document.write( "---------------------------------- Subtract \n" ); document.write( "-5x = -12 \n" ); document.write( "x = 12/5 \n" ); document.write( "---------- \n" ); document.write( "Sub for x in Eqn A or B to find y \n" ); document.write( "Sub for x & y in any Eqn to find z \n" ); document.write( " |