document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1082703>Question 1082703</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three electricians can fix 10 short circuits in 2 hours. how much time will four electricians need to fix 15 short circuits?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #696760 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=696760\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3 electricians at 2 hours each is 6 man-hours<BR>\n" );
document.write( "10 shorts are fixed in 6*60 = 360 man-minutes<BR>\n" );
document.write( "360/10 = 36 man-minutes per short<BR>\n" );
document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<BR>\n" );
document.write( "For 4 to fix 15:<BR>\n" );
document.write( "15*36 = 378 man-minutes<BR>\n" );
document.write( "378/4 = 94.5 or 94<sup>1</sup>&frasl;<sub>2</sub> minutes or 1hr34<sup>1</sup>&frasl;<sub>2</sub> minutes </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );