document.write( "Question 1082665: x+y+z=12
\n" ); document.write( "x-y+z=6
\n" ); document.write( "x-y-z=o.
\n" ); document.write( "So x,y,and,z=?
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Algebra.Com's Answer #696736 by MathTherapy(10552)\"\" \"About 
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x+y+z=12
\n" ); document.write( "x-y+z=6
\n" ); document.write( "x-y-z=o.
\n" ); document.write( "So x,y,and,z=?
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x + y + z = 12 ----- eq (i)
\n" ); document.write( "x - y + z = 6 ------ eq (ii)
\n" ); document.write( "x - y - z = 0 ------ eq (iii)
\n" ); document.write( "1) ADD eqs (i) & (iii) to ELIMINATE y and z and find the value of x
\n" ); document.write( "2) Subtract eq (ii) from eq (i), or vice-versa to ELIMINATE x and z and find the value of y
\n" ); document.write( "3) Subtract eq (iii) from eq (ii) or vice-versa to ELIMINATE x and y and determine the value of z.
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