document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1082657>Question 1082657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 8.03 inches more than half of its width. If the perimeter is 37.48 inches <BR>\n" );
document.write( "Find the demensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #696724 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=696724\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L + 2W = Perimeter<BR>\n" );
document.write( "L = 1/2W + 8.03 substitute for L above:<BR>\n" );
document.write( "2(1/2W + 8.03) + 2W = 37.48<BR>\n" );
document.write( "W + 16.06 + 2W = 37.48<BR>\n" );
document.write( "3W = 21.42<BR>\n" );
document.write( "W = 7.14<BR>\n" );
document.write( "L = 1/2W + 8.03 = 1/2(7.14)+8.03 = 11.6<BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "2L + 2W = 37.48<BR>\n" );
document.write( "2(7.14) + 2(11.6) = 37.48 Correct </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );