document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95641>Question 95641</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble. Can someone please help me.\r<BR>\n" );
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document.write( "Solve:<BR>\n" );
document.write( "-3(x+1)=2(x-8)+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69668 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69668\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for x:<BR>\n" );
document.write( "-3(x+1) = 2(x-8)+3  First, apply the \"distributive property\" to both sides of the equation.<BR>\n" );
document.write( "-3x-3 = 2x-16+3 Simplify.<BR>\n" );
document.write( "-3x-3 = 2x-13 Add 3x to both sides.<BR>\n" );
document.write( "-3 = 5x-13 Add 13 to both sides.<BR>\n" );
document.write( "10 = 5x Finally, divide both sides by 5.<BR>\n" );
document.write( "2 = x  or  x = 2\r<BR>\n" );
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document.write( "Check:  Substitute x = 2 in the original equation.<BR>\n" );
document.write( "-3(2+1) = 2(2-8)+3 Simplify.<BR>\n" );
document.write( "-6-3 = 4-16+3 Evaluate.<BR>\n" );
document.write( "-9 = 7-16<BR>\n" );
document.write( "-9 = -9 It checks!<BR>\n" );
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