document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95364>Question 95364</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3/x+1/y=1<BR>\n" );
document.write( "2/x+5/y=18 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69667 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69667\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/x+1/y=1 <BR>\n" );
document.write( "2/x+5/y=18<BR>\n" );
document.write( "A. Multiply xy times both sides 3y+x=xy<BR>\n" );
document.write( "Multiply xy times both sides 2y+5x=18xy<BR>\n" );
document.write( "since 18xy is 18 times larger than xy we can make an equation.<BR>\n" );
document.write( "2y+5x=18(3y+x)<BR>\n" );
document.write( "2y+5x=54y+18x<BR>\n" );
document.write( "subtract 5x and 54y from both sides. -52y=13x<BR>\n" );
document.write( "divide 13 into both sides x=-4y<BR>\n" );
document.write( "Plug -4y into 3y+x=xy and we get 3y-4y=-4y^2<BR>\n" );
document.write( "-y=-4y^2<BR>\n" );
document.write( "add 4y^2 to both sides. 4y^2-y=0<BR>\n" );
document.write( "Quadratic equation: y=0 and y=.25 but since division by 0 in the original equations would occur if y=0 then y=.25 is the only answer.<BR>\n" );
document.write( "Substitute .25 for y in 3/x+1/y=1 <BR>\n" );
document.write( "3/x+1/.25=1<BR>\n" );
document.write( "EdJones<BR>\n" );
document.write( "3/x+4=1<BR>\n" );
document.write( "3/x=-3<BR>\n" );
document.write( "3=-3x<BR>\n" );
document.write( "x=-1<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "Plug -1 and .25 into 2/x+5/y=18<BR>\n" );
document.write( "2/-1+5/.25=18<BR>\n" );
document.write( "-2+20=18<BR>\n" );
document.write( "EdJones </SPAN>\n" );
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