document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1082597>Question 1082597</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pleas help me solve and understand the this problem: A biologist is studying a fish. she uses the fishes length in cm L to estimate the fishes age in years T according to the formula T=19-5ln(53-L)\r<BR>\n" );
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document.write( "a) estimate the age of a 35 cm fish \r<BR>\n" );
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document.write( "b) according to the formula what length should a 10yr old fish be.\r<BR>\n" );
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document.write( "pleas include steps when solving the problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #696657 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=696657\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> T = 19 - 5ln(53-L)<BR>\n" );
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document.write( "a)  T = 19 - 5ln(53-35)<BR>\n" );
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document.write( "T = 19 - 5ln(18)<BR>\n" );
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document.write( "T = 19 - 5 * 2.8904 = 4.548<BR>\n" );
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document.write( "35 cm fish is approximately 4.5 years old<BR>\n" );
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document.write( "b)  10 = 19 - 5ln(53-L)<BR>\n" );
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document.write( "5ln(53-L) = 19 - 10 = 9<BR>\n" );
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document.write( "ln(53-L) = 9/5 = 1.8 <BR>\n" );
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document.write( "53-L = inverse log(base e) of 1.8 = 6.0496<BR>\n" );
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document.write( "L = 53 - 6.0496 = 46.9504 approximately 47<BR>\n" );
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document.write( "A 10 year old fish should be 47 cm long<BR>\n" );
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