document.write( "Question 1082577: In Still water, a boat averages 18 miles per hour. It takes the same amount of time to travel 10 miles downstream, with the current. As it does 5 miles Upstream, against the current. What is the rate of the water's current? \n" ); document.write( "
Algebra.Com's Answer #696634 by josmiceli(19441) You can put this solution on YOUR website! Let \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Let \n" ); document.write( "---------------------------------------------------------- \n" ); document.write( "Going downstream: \n" ); document.write( "(1) \n" ); document.write( "Going upstream: \n" ); document.write( "(2) \n" ); document.write( "------------------------- \n" ); document.write( "(1) \n" ); document.write( "Plug (1) into (2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "The rate of thr current is 6 mi/hr \n" ); document.write( "-------------------------------- \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "--------------------------- \n" ); document.write( "Note: \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " \n" ); document.write( " |