document.write( "Question 1082468: The probability of passing a class is 60%. What is the probability that 1 out of 20 students pass the class?\r
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document.write( "A) 1.2*10^-4%
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document.write( "B) 2.3*10^-4%
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document.write( "C) 3.3*10^-5%
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document.write( "D) 5.6*10^-5% \n" );
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Algebra.Com's Answer #696615 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the formula for the binomial probability is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(x) = p^x * q^(n-x) * c(n,x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when p = .6, q = .4 because q = 1 - p.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 1 and n = 20, the formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(1) = .6^1 * .4^19 * c(20,1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c(20,10) is the combination formula of c(n,x) = n! / (x!*(n-x)!)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when n = 20 and x = 1, this formula becomes c(20,1) = 20! / (1! * 19!)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this can be written as c(20,1) = (20 * 19!) / (1! * 19!)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify this to get c(20,1) = 20/1 = 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(1) = .6^1 * .4^19 * c(20,1) becomes p(1) = .6^1 * .4^19 * 20.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for p(1) to get p(1) = 3.298534883 * 10^(-7)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "round this to 1 decimal digit and this becomes p(1) = 3.3 * 10^(-7)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply this by 100 to make it a percent and you get p(1) = 330 * 10^(-7)%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "convert this to scientific format to get p(1) = 3.3 * 10^(-5)%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to convert to scientific format, there must be only 1 digit to the left of the decimal point\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "330 * 10^(-7)% has 3 digits to the left of the decimal point because the decimal point is implied after the 330.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it actually looks like 330. * 10^(-7)%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to get it to be 3.3, you have to divide 330 by 100 and multiply 10^(-7) by 100.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you would get p(1) = 3.3 * 10^(-7) * 100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10^(-7) * 100 is the same as 10^(-7) * 10^2 which results in 10^(-7+2) which results in 10^(-5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you end up with p(1) = 3.3 * 10^(-5)%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that looks like selection C.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |