document.write( "Question 1082541: tickets for a certain concert sold for $6, $8 and 12$ each. there were 280 more 6$ tickets sold than 8$ and 12$ tickets together and the total revenue from 840 tickets was $6080. how many tickets were sold? \n" ); document.write( "

Algebra.Com's Answer #696607 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Let  x = # of $8 tickets and y = # of $12 tickets.\r\n" );
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document.write( "Then the number of $6 tickets is (x+y+280).\r\n" );
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document.write( "The \"items\" equation is\r\n" );
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document.write( "(x + y + 280) + x + y = 840,    (1)\r\n" );
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document.write( "The \"value\" equation is\r\n" );
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document.write( "6(x+y+280) + 8x + 12y = 6080.   (2)\r\n" );
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document.write( "Simplify\r\n" );
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document.write( " 2x +  2y =  560            (560 = 840-280)\r\n" );
document.write( "14x + 18y = 4400            (4400 = 6080-6*280)\r\n" );
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document.write( "Or even better\r\n" );
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document.write( " x +  y = 280\r\n" );
document.write( "7x + 9y = 2200.\r\n" );
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document.write( "Solve by any method you know (substitution, elimination).\r\n" );
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