document.write( "Question 95605: The volume of a can of soup is 144 PI inches cubed. The radius of the can is 6 inches. What is the height of the can? \n" ); document.write( "
Algebra.Com's Answer #69658 by bucky(2189)\"\" \"About 
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Given that the volume of a cylindrical can is:
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\n" ); document.write( "\"144%2Api\" cubic inches
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\n" ); document.write( "and also given that the radius of the can is 6 inches.
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\n" ); document.write( "To find the height of the can you can begin by noting that the formula for finding the volume V
\n" ); document.write( "of a cylinder is based on multiplying the area A of the circular base of the cylinder times
\n" ); document.write( "the height H. In equation form this is:
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\n" ); document.write( "\"V+=+A+%2A+H\"
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\n" ); document.write( "and because A (the area of the circular base) can be found from the equation \"A+=+pi%2AR%5E2\" in
\n" ); document.write( "which R is the radius of the circle, we can substitute this value for A into the Volume formula
\n" ); document.write( "to get:
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\n" ); document.write( "\"V+=+pi%2AR%5E2+%2AH\"
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\n" ); document.write( "The problem tells you that the value of R is 6 inches and the value of V is \"144%2Api\".
\n" ); document.write( "Substitute these values into the equation and you get:
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\n" ); document.write( "\"144%2Api+=+pi%2A6%5E2%2AH\"
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\n" ); document.write( "Since \"pi\" is a factor on both sides you can divide both sides by \"pi\" to cancel
\n" ); document.write( "the \"pi\" and reduce the equation to:
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\n" ); document.write( "\"144+=+6%5E2+%2AH\"
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\n" ); document.write( "Now recognize that \"6%5E2+=+36\". Substitute 36 into the equation and get:
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\n" ); document.write( "\"144+=+36%2AH\"
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\n" ); document.write( "Solve for H by dividing both sides by 36 to get:
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\n" ); document.write( "\"144%2F36+=+H\"
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\n" ); document.write( "and this divides out evenly to give you that:
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\n" ); document.write( "\"H+=+4\"
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\n" ); document.write( "Since every dimension was in inches you know that the height H is 4 inches.
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\n" ); document.write( "Hope this helps you to understand the problem and a way that you can work it.
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