document.write( "Question 1082461: A number is 7 times the sum of its digits. If the digits are reversed, the new number is 30 less than twice the original. \n" ); document.write( "
Algebra.Com's Answer #696526 by Fombitz(32388)\"\" \"About 
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A and B are integers from 0-9.
\n" ); document.write( "Let the original number be \"10A%2BB\".
\n" ); document.write( "The sum of its digits would be \"A%2BB\".
\n" ); document.write( "Digits reversed would be \"10B%2BA\".
\n" ); document.write( "So,
\n" ); document.write( "\"10A%2BB=7%28A%2BB%29\"
\n" ); document.write( "\"10A%2BB=7A%2B7B\"
\n" ); document.write( "\"3A=6B\"
\n" ); document.write( "1.\"A=2B\"
\n" ); document.write( "and
\n" ); document.write( "\"10B%2BA=2%2810A%2BB%29-30\"
\n" ); document.write( "\"10B%2BA=20A%2B2B-30\"
\n" ); document.write( "2.\"19A-8B=30\"
\n" ); document.write( "Substituting from 1 into 2,
\n" ); document.write( "\"19%282B%29-8B=30\"
\n" ); document.write( "\"38B-8B=30\"
\n" ); document.write( "\"30B=30\"
\n" ); document.write( "Solve for B, then use either equation to solve for A.\r
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