document.write( "Question 1082433: X+y=a and x2+y2=b then value of x3+y3 will be \n" ); document.write( "
Algebra.Com's Answer #696512 by ikleyn(52781)\"\" \"About 
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document.write( "You are given\r\n" );
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document.write( "x + y = a,           (1)\r\n" );
document.write( "\"x%5E2+%2B+y%5E2\" = b           (2)\r\n" );
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document.write( "You are asked to find the value of \"x%5E3+%2B+y%5E3\".\r\n" );
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document.write( "Square the equality (1) (both sides). You will get\r\n" );
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document.write( "\"x%5E2+%2B+2xy+%2B+y%5E2\" = \"a%5E2\".     (3)\r\n" );
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document.write( "Subtract (2) from (3) (both sides). You will get\r\n" );
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document.write( "2xy = \"b+-+a%5E2\".         (4)\r\n" );
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document.write( "Now we are ready to evaluate \"x%5E3+%2B+y%5E3\".\r\n" );
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document.write( "  \"x%5E3+%2B+y%5E3\" = \"%28x%2By%29%2A%28x%5E2-xy%2By%5E2%29\"       (I suppose you know this classic/basic factoring)\r\n" );
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document.write( "= \"a%2A%28%28x%5E2+%2B+y%5E2%29-+xy%29%29\"                 (I just replaced the factor x+y by its value a, according to (1))\r\n" );
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document.write( "= \"a%2A%28b+-+%28%28b+-+a%5E2%29%2F2%29%29\"                (I just replaced \"x%5E2+%2B+y%5E2\" by 'b' and replaced  xy  by  \"%28b-a%5E2%29%2F2\", due to (4) )\r\n" );
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document.write( "= \"a%2A%28a%5E2%2Bb%29%2F2\" = \"%28a%5E3%2Bab%29%2F2\".\r\n" );
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