document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1082301>Question 1082301</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a. How many ways are there of arranging three different math books, five different history books, and four different French books side by side on a shelf if the books of the same subject must be together?\r<BR>\n" );
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document.write( "b. How many arrangements of these books are possible if a math book must be on each end and the French books are together?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #696349 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=696349\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have 3 math, they can each be placed on one end, the other, or in the middle, so this is 3!<BR>\n" );
document.write( "Now you have 5 hist. books, they can each go in any of 5 positions: 5!<BR>\n" );
document.write( "And the French books 4!<BR>\n" );
document.write( "Finally, you have books on three subjects, they are grouped but the group can go on the left of the other groups, or the middle, or the right: 3!<BR>\n" );
document.write( "3! x 5! x 4! x 3! = 103,680 ways </SPAN>\n" );
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