document.write( "Question 1082287: Write an equation for the ellipse, satisfying the following conditions. Foci at (0,-2) and (0,2); the point (3,2) on the ellipse \n" ); document.write( "
Algebra.Com's Answer #696339 by natolino_2017(77)![]() ![]() ![]() You can put this solution on YOUR website! The mid point between the two focus is the center of the ellipse.\r \n" ); document.write( "\n" ); document.write( "In this case, Center= ((0+0)/2 , (2+-2)/2) =(0 , 0).\r \n" ); document.write( "\n" ); document.write( "Let P = (3 , 2), F1 = (0 , -2), F2 =(0 , 2)\r \n" ); document.write( "\n" ); document.write( "\"The sum of the distance of a point of the ellipse to every Focus, is constant and equal to the double of the Semi-major axis (A)\"\r \n" ); document.write( "\n" ); document.write( "PF1 + PF2 = 2A.\r \n" ); document.write( "\n" ); document.write( "5 + 3 = 2A\r \n" ); document.write( "\n" ); document.write( "A = 4\r \n" ); document.write( "\n" ); document.write( "Let C: distance from the center to a focus.\r \n" ); document.write( "\n" ); document.write( " C = 2.\r \n" ); document.write( "\n" ); document.write( "A^2 = B^2 + C^2\r \n" ); document.write( "\n" ); document.write( " B = sqrt(12).\r \n" ); document.write( "\n" ); document.write( "So the equation is\r \n" ); document.write( "\n" ); document.write( " x^2/12 + y^2/16 = 1.\r \n" ); document.write( "\n" ); document.write( "observation: the Focus doesn't belong to the ellipse.\r \n" ); document.write( "\n" ); document.write( "@natolino_ \n" ); document.write( " |