document.write( "Question 1082283: 2% of the time, a baseball player gets a double. 15% of the time a baseball player gets a single. 8% of the time a baseball player gets a home run, and 40% of the time the baseball player strikes out. What is the probability that the baseball player will get a home run or will strike out?\r
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document.write( "A) 48%
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document.write( "B) 3.2%
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document.write( "C) 25%
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document.write( "D) 36% \n" );
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Algebra.Com's Answer #696337 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! The events \"get a home run\" and \"strikeout\" are mutually exclusive events. If one event happens, then the other cannot happen. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Because the events are mutually exclusive, this allows us to simply add the corresponding probabilities for getting a home run (8%) and striking out (40%)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Keep in mind that \n" ); document.write( "8% = 8/100 = 0.08 \n" ); document.write( "40% = 40/100 = 0.40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(home run OR striking out) = P(home run) + P(striking out) \n" ); document.write( "P(home run OR striking out) = 0.08 + 0.40 \n" ); document.write( "P(home run OR striking out) = 0.48 \n" ); document.write( "P(home run OR striking out) = 48%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: Choice A) 48% \n" ); document.write( " |