document.write( "Question 1082210: Urn 1 contains 3 red balls and 4 black balls. Urn 2 contains 4 red balls and 2 black balls. Urn 3 contains 6 red balls and 5 black balls. If an urn is selected at random and a ball is drawn, find the probability it will be red. \n" ); document.write( "

Algebra.Com's Answer #696269 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
Urn 1 = 3 red balls and 4 black balls
\n" ); document.write( "Urn 2 = 4 red balls and 2 black balls
\n" ); document.write( "Urn 3 = 6 red balls and 5 black balls\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "There are 3+4+6 = 13 red balls.
\n" ); document.write( "There are a total of 3+4+4+2+6+5 = 24 balls\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "P(red) = Probability of picking red ball
\n" ); document.write( "P(red) = (number of red balls)/(number of balls total)
\n" ); document.write( "P(red) = 13/24
\n" ); document.write( "P(red) = 0.54167 ... approximate
\n" ); document.write( "P(red) = 54.167% ... approximate\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The answer as a fraction is 13/24
\n" ); document.write( "The answer as a decimal is approximately 0.54167
\n" ); document.write( "The answer as a percent is approximately 54.167% \n" ); document.write( "

\n" );