document.write( "Question 95589This question is from textbook Prentice Hall Algebra 1
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document.write( ": 2/3+3y=5y-2/15\r
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document.write( "i tried to put a 1 over the 3 and 5 with y's but i still couldn't figure it out. also i tried to subtract 2/3 from each side. \n" );
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Algebra.Com's Answer #69626 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2/3+3y=5y-2/15 \n" ); document.write( "Subtract 3y from both sides and gather the numbers on one side:\r \n" ); document.write( "\n" ); document.write( "2y = (2/3)+(2/15) \n" ); document.write( "2y = (10/15) + (2/15) \n" ); document.write( "2y = 12/15 \n" ); document.write( "y = 6/15 \n" ); document.write( "y = 2/5 \n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |