document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1082143>Question 1082143</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 28 peons can finish the job in 60 days,. At the start of 16th day 5 peons were laid off and after the 45th days, 10 more peons were hired. How many days they were delayed finishing the job? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #696238 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=696238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 28 peons x 60 days=1680 peons in 1 day<BR>\n" );
document.write( "28 x 15/1680=1/4 of the work done after 15 days<BR>\n" );
document.write( "(46-16) x 23/1680 +420/1680=1110/1680ths of the work done<BR>\n" );
document.write( "1680-1110=570/1680 of the work left<BR>\n" );
document.write( "570/1680 / 33/1680=570/33=17.27 days of work left after the 45th day<BR>\n" );
document.write( "45+17.27-60=2.272727 days delayed finishing the job. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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