document.write( "Question 1082142: The expression x^4 + ax^3 + 5x^2 + bx + 6 when divide by (x-2), the remainder is 16 and then divided by (x+1) leaves remainder of 10. Find the value of a. \n" ); document.write( "

Algebra.Com's Answer #696219 by solver91311(24713) $\"\"$ $\"About$

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document.write( " 2   1    a         5      b             6\r\n" );
document.write( "          2      2a+4     4a+18   8a+2b+36\r\n" );
document.write( "     -------------------------------------\r\n" );
document.write( "     1    a+2    2a+9   4a+b+18   8a+2b+42\r\n" );
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document.write( "-1   1    a         5      b             6 \r\n" );
document.write( "           -1    -a+1    a  -6     -a-b+ 6\r\n" );
document.write( "     -------------------------------------\r\n" );
document.write( "          a-1    -a+6    a+b-6     -a-b+12\r\n" );
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document.write( "     8a + 2b + 42 =  16\r\n" );
document.write( "     -a -  b + 12 =  10\r\n" );
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document.write( "     8a + 2b      = -26\r\n" );
document.write( "     -a -  b      = - 2\r\n" );
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document.write( "     8a + 2b      = -26\r\n" );
document.write( "    -2a - 2b      = - 4\r\n" );
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document.write( "     6a           = -30\r\n" );
document.write( "      a           = - 5\r\n" );
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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