document.write( "Question 1082119: Which of the following expressions is equal to -3x^2-27
\n" ); document.write( "A ) (-3x-3i)(x-9i)
\n" ); document.write( "B ) (-3x-9i)(x+3i)
\n" ); document.write( "C ) (-3x+3i)(x+9i)
\n" ); document.write( "D ) (-3X+9i)(x+3i)
\n" ); document.write( "i know i have to factor (i think) to solve it but i'm having trouble when it comes to getting the final form ( cant think of the right term)
\n" ); document.write( "

Algebra.Com's Answer #696213 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"-3x%5E2-27\"\r
\n" ); document.write( "\n" ); document.write( "\"-3%28x%5E2%2B9%29\"\r
\n" ); document.write( "\n" ); document.write( "\"-3%28x%5E2%2B3%5E2%29\"........here we have the sum of squares \"%28x%5E2%2B3%5E2%29\" and we can write it as the difference of squares if we write \"3%5E2\" as \"-3%5E2%28-1%29\", and we know that \"-1=i%5E2\"; so, we have \"%28x%5E2-3%5E2i%5E2%29\" or
\n" ); document.write( "\"%28x%5E2-%283i%29%5E2%29\" now factor it as the difference of the squares and you have \"x%5E2%2B9=%28x+-3i%29+%28x+%2B+3i%29\"\r
\n" ); document.write( "\n" ); document.write( "plug it in:
\n" ); document.write( "\"-3%28x+-3i%29%28x+%2B+3i%29\"....multiply \"-3%28x+-3i%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28-3x+-%28-3%293i%29%28x+%2B+3i%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28-3x+%2B9i%29%28x+%2B+3i%29\"\r
\n" ); document.write( "\n" ); document.write( "answer:\r
\n" ); document.write( "\n" ); document.write( "D ) \"%28-3X%2B9i%29%28x%2B3i%29\"
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