document.write( "Question 1082101: A coin is biased such that the head is twice as likely to occur as tail. If this coin is tossed 4 times, find
\n" ); document.write( "i- the sample space
\n" ); document.write( "ii- the probability of having at least 2 heads
\n" ); document.write( "iii- the probability of having exactly 3 heads
\n" ); document.write( "iv- the probability of having at most 4 heads.
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Algebra.Com's Answer #696177 by Boreal(15235)\"\" \"About 
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HHHH
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\n" ); document.write( "Exactly two heads in 4 tosses: 6 ways of having them 4C2
\n" ); document.write( "The denominator of the product of the probabilities is always 81. The numerator numbers change in order but not in product, and they are 2*2*1*1=4. Multiply by 6 and get 24/81=8/27
\n" ); document.write( "exactly 3 heads is 4 * 2*2*2*1/87=32/81
\n" ); document.write( "exactly 4 heads is 2*2*2*2/81=16/81
\n" ); document.write( "(and 1 head and 0 heads for completeness:
\n" ); document.write( "1:2*4/81=8/81
\n" ); document.write( "0:1/81
\n" ); document.write( "Sum is 81/81
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