document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1082074>Question 1082074</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bookstore had 98 copies of a magazine. Yesterday, it sold 2/7 of them. Today, it sold 4/7 of what remained. How many copies does the bookstore have left? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #696144 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=696144\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> After the first day there were 5/7 of the original number remaining:  70<BR>\n" );
document.write( "After the 2nd day there were 3/7 remaining from the number the 2nd day started with (which is the same number as we ended with AFTER the first day):  70*3/7 = 30<BR>\n" );
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document.write( "Or, we can combine everything into one calculation:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+98%2A%285%2F7%29%2A%283%2F7%29+=+%2898%2F49%29%2A5%2A3+=+2%2A5%2A3+=+highlight%2830%29+ ALIGN=MIDDLE  ALT=\"+98%2A%285%2F7%29%2A%283%2F7%29+=+%2898%2F49%29%2A5%2A3+=+2%2A5%2A3+=+highlight%2830%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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