document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=95572>Question 95572</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I have 2(N sq. + 1)-3(2N sq. - 3) and I need to solve for N, how do I work the squared N?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #69612 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=69612\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2(n^2+1)-3(2n^2-3)<BR>\n" );
document.write( "2n^2+2-6n^2+9<BR>\n" );
document.write( "-4n^2+11 answer. <BR>\n" );
document.write( "Unless you set this equation=0. then:<BR>\n" );
document.write( "-4n^2+11=0<BR>\n" );
document.write( "-4n^2=-11<BR>\n" );
document.write( "n^2=-11/-4<BR>\n" );
document.write( "n^2=11/4 <BR>\n" );
document.write( "n=sqrt11/4<BR>\n" );
document.write( "n=sqrt2.75<BR>\n" );
document.write( "n=1.683 answer.<BR>\n" );
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