document.write( "Question 1082028: Domain of f(x)=sqrt of x divided by x-3 \n" ); document.write( "

Algebra.Com's Answer #696099 by Edwin McCravy(20056) $\"\"$ $\"About$

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document.write( "Domain of \r\n" );
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document.write( "If three were no denominators or square roots containing x\r\n" );
document.write( "the domain would be \r\n" );
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document.write( "But this function has BOTH!\r\n" );
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document.write( "So we set what's under the square root greater than or equal to zero\r\n" );
document.write( "and we set the denominator not equal to 0.\r\n" );
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document.write( "So we have  and \r\n" );
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document.write( "Solving  we get \r\n" );
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document.write( "Now we see that there is no need to require that , for\r\n" );
document.write( "if x is greater than or equal 3, then it's automatically not equal \r\n" );
document.write( "to 0, so we only need to write the domain either in set builder\r\n" );
document.write( "for as \r\n" );
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document.write( "{x | x ≧ 3}\r\n" );
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document.write( "or in interval notation as\r\n" );
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document.write( "Edwin

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