document.write( "Question 1081864: Suppose that
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document.write( "55%
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document.write( " of all adults in a certain community are obese and that
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document.write( "36%
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document.write( " suffer from diabetes. If
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document.write( "14%
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document.write( " of the adults in this community are both obese and suffering from diabetes, what is the probability that a randomly chosen adult in this community is obese or suffers from diabetes (or both)?
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Algebra.Com's Answer #696090 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! p(A or B)=p(A)+p(B)-p(A and B) \n" ); document.write( "=0.55+0.36-0.14=0.77. The 0.14 is subtracted to deal with double counting. \n" ); document.write( " |