document.write( "Question 1081988: If, in 7 years, Susan will be 2 times as old as she was 3 years ago, what is Susan’s present age? \n" ); document.write( "
Algebra.Com's Answer #696046 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "let Susan’s present age be: \"x\"
\n" ); document.write( "in \"7\" years, Susan will be: \"x%2B7\"
\n" ); document.write( " \"3\" years ago she was:\"x-3\"\r
\n" ); document.write( "\n" ); document.write( "and if \"x%2B7\" will be \"2\" times \"x-3%7D%7D%2C+we+have%0D%0A%0D%0A%7B%7B%7Bx%2B7=2%28x-3%29\".........solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B7=2x-6\"\r
\n" ); document.write( "\n" ); document.write( "\"6%2B7=2x-x\"\r
\n" ); document.write( "\n" ); document.write( "\"13=x\"\r
\n" ); document.write( "\n" ); document.write( "so, Susan’s present age is \"13\" \r
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\n" ); document.write( "\n" ); document.write( "check:
\n" ); document.write( "present age is \"13\"\r
\n" ); document.write( "\n" ); document.write( "in \"7\" years, Susan will be: \"20\"
\n" ); document.write( "\"3\" years ago she was:\"10\"\r
\n" ); document.write( "\n" ); document.write( "\"20=2%2810%29\"\r
\n" ); document.write( "\n" ); document.write( "\"20=20\".........which confirms our result\r
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