document.write( "Question 1081986: Can you please answer this question for finding the complex number z = x + yi that satisfies the equation (1+3i)z + (4-2i)z = 10+4i
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Algebra.Com's Answer #696045 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
(1+3i)z + (4-2i)z = 10+4i
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\n" ); document.write( "factor z on left side of =
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\n" ); document.write( "z(1+3i +4-2i) = 10+4i
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\n" ); document.write( "z(5+i) = 10+4i
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\n" ); document.write( "divide both sides of = by (5+i)
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\n" ); document.write( "z = (10+4i) / (5+i)
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\n" ); document.write( "multiply the numerator and denominator by (5-i)
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\n" ); document.write( "z = ((10+4i)*(5-i)) / ((5+i)*(5-i))
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\n" ); document.write( "z = (10+4i)*(5-i) / 26
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\n" ); document.write( "Note that -i^2 = -(-1) = 1
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\n" ); document.write( "(10+4i) and 26 are divisible by 2
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\n" ); document.write( "z = (5+2i)*(5-i) / 13
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\n" ); document.write( "z = (25+10i-5i-2i^2) / 13
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\n" ); document.write( "z = (27+5i) / 13
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