document.write( "Question 1081986: Can you please answer this question for finding the complex number z = x + yi that satisfies the equation (1+3i)z + (4-2i)z = 10+4i
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document.write( "Thank you so much if you help!! \n" );
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Algebra.Com's Answer #696045 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! (1+3i)z + (4-2i)z = 10+4i \n" ); document.write( ": \n" ); document.write( "factor z on left side of = \n" ); document.write( ": \n" ); document.write( "z(1+3i +4-2i) = 10+4i \n" ); document.write( ": \n" ); document.write( "z(5+i) = 10+4i \n" ); document.write( ": \n" ); document.write( "divide both sides of = by (5+i) \n" ); document.write( ": \n" ); document.write( "z = (10+4i) / (5+i) \n" ); document.write( ": \n" ); document.write( "multiply the numerator and denominator by (5-i) \n" ); document.write( ": \n" ); document.write( "z = ((10+4i)*(5-i)) / ((5+i)*(5-i)) \n" ); document.write( ": \n" ); document.write( "z = (10+4i)*(5-i) / 26 \n" ); document.write( ": \n" ); document.write( "Note that -i^2 = -(-1) = 1 \n" ); document.write( ": \n" ); document.write( "(10+4i) and 26 are divisible by 2 \n" ); document.write( ": \n" ); document.write( "z = (5+2i)*(5-i) / 13 \n" ); document.write( ": \n" ); document.write( "z = (25+10i-5i-2i^2) / 13 \n" ); document.write( ": \n" ); document.write( "***************** \n" ); document.write( "z = (27+5i) / 13 \n" ); document.write( "***************** \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |