document.write( "Question 1081958: a two digit number is formed by using two consecutive integers, such that the smaller integer takes the tens place. by what percentage is the number obtained by reversing the digits more than the original number? \n" ); document.write( "
Algebra.Com's Answer #696030 by math_helper(2461)\"\" \"About 
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a two digit number is formed by using two consecutive integers, such that the smaller integer takes the tens place. by what percentage is the number obtained by reversing the digits more than the original number?
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\n" ); document.write( "\n" ); document.write( "12 —> 21 ==> 9/12 = 0.75 or 75% increase from 12 to get to 21
\n" ); document.write( "45 —> 54 ==> 9/45 = 0.20 or 20% increase from 45 to get to 54\r
\n" ); document.write( "\n" ); document.write( "Since the percentage is a function of what the original two digit number is, the best we can do is find a formula for the percentage increase.\r
\n" ); document.write( "\n" ); document.write( "Let n be the initial (ten's) digit in the unswapped number (e.g. n=1 in 12):\r
\n" ); document.write( "\n" ); document.write( "Then our two digit number is 10n + (n+1) = 11n + 1\r
\n" ); document.write( "\n" ); document.write( "Swapping digits will always increase the number by 9 so the percentage increase is:
\n" ); document.write( " \"+highlight%28%289%2F%2811n%2B1%29%29+%2A+100%29+\" %\r
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