document.write( "Question 1081922: You roll a number cube twice. Find P(odd, then not 1). Write the probability as a fraction in simplest form.\r
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document.write( "So far I have P odd = 6/12 or 1/2 then I think (then not 1) is 6/12 - 2/12 = 4/12 or 1/3.\r
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document.write( "Am I correct? \n" );
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Algebra.Com's Answer #695964 by Fombitz(32388) You can put this solution on YOUR website! \n" ); document.write( "First roll : odd. \n" ); document.write( "Not sure why you have 6 out of 12. \n" ); document.write( "There are only 6 possible outcomes. \n" ); document.write( "Three of them are odd. \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Second roll : not a 1. \n" ); document.write( "Again six possible outcomes, five are not 1. \n" ); document.write( " \n" ); document.write( "So together, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |