document.write( "Question 1081913: The equation of a parabola is given.\r
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document.write( "y=14x2−3x+18\r
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document.write( "What are the coordinates of the focus of the parabola? \n" );
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Algebra.Com's Answer #695963 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Write in vertex form. \n" ); document.write( "vertex is at -b/2a=3/28 for x and y=(14*9/28^2)x^2-9/28+18=126/784-252/784+18=17.84 \n" ); document.write( "ax^2+bx+c=f(x) \n" ); document.write( "f(1)=29 \n" ); document.write( "f(-1)=35 \n" ); document.write( "y=a(x-0.107)^2+17.84, 14(x-0.107)^2+17.84 \n" ); document.write( "29=a(.893)^2+17.84 \n" ); document.write( "11.16/(0.893)^2=a=14, which it should be. \n" ); document.write( "focus is at (h, k+1/(4a)); k+1/(4a)=17.84+1/56=17.86 \n" ); document.write( "that is at (0.107, 17.86) \n" ); document.write( " \n" ); document.write( ", \n" ); document.write( " \n" ); document.write( " |