document.write( "Question 1081913: The equation of a parabola is given.\r
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\n" ); document.write( "\n" ); document.write( "y=14x2−3x+18\r
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\n" ); document.write( "\n" ); document.write( "What are the coordinates of the focus of the parabola?
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Algebra.Com's Answer #695963 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
Write in vertex form.
\n" ); document.write( "vertex is at -b/2a=3/28 for x and y=(14*9/28^2)x^2-9/28+18=126/784-252/784+18=17.84
\n" ); document.write( "ax^2+bx+c=f(x)
\n" ); document.write( "f(1)=29
\n" ); document.write( "f(-1)=35
\n" ); document.write( "y=a(x-0.107)^2+17.84, 14(x-0.107)^2+17.84
\n" ); document.write( "29=a(.893)^2+17.84
\n" ); document.write( "11.16/(0.893)^2=a=14, which it should be.
\n" ); document.write( "focus is at (h, k+1/(4a)); k+1/(4a)=17.84+1/56=17.86
\n" ); document.write( "that is at (0.107, 17.86)
\n" ); document.write( "\"graph%28300%2C300%2C-5%2C5%2C-10%2C30%2C14x%5E2-3x%2B18%29\"
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