document.write( "Question 1081862: A particle moves in a straight line so that its distance, s m, from a fixed point A on the line is given by s=2t^2-4t+9, for t less than or equal to 3, where t is the time in seconds after passing through a point B on the line.
\n" ); document.write( "(a) the total distance travelled by the particle in the period of t=0 to t=3. Ans=10m
\n" ); document.write( "(b) At t=3, the acceleration of the particle is changed to (t − 8)m/s2 , the instantaneous velocity remaining unchanged. Find the next value of t at which the particle comes to instantaneous rest. Ans= 5s
\n" ); document.write( "

Algebra.Com's Answer #695959 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
a)
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "Looking at the graph, the particle travels from 9 to 7 in the 1st second, from 7 to 9 in the 2nd second and from 9 to 15 in the 3rd second.
\n" ); document.write( "So it traveled,
\n" ); document.write( "\"D=abs%287-9%29%2Babs%289-7%29%2Babs%2815-9%29=2%2B2%2B6=10\"\"m\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "b) Find the instantaneous velocity when \"t=3\",
\n" ); document.write( "\"v=ds%2Fdt=4t-4=4%283%29-4=12-4=8\"\"m%2Fs\"
\n" ); document.write( "So then integrate the new acceleration to get the new velocity,
\n" ); document.write( "\"v=int%28a%2Cdt%2Ct=3%2Ct%29=int%28%28t-8%29%2Cdt%2Ct=3%2Ct%29=t%5E2%2F2-8t%2BC\"
\n" ); document.write( "When \"t=3\",\"v=8\",
\n" ); document.write( "\"8=%283%29%5E2%2F2-8%283%29%2BC\"
\n" ); document.write( "\"8=9%2F2-24%2BC\"
\n" ); document.write( "\"C=32-9%2F2\"
\n" ); document.write( "\"C=64%2F2-9%2F2\"
\n" ); document.write( "\"C=55%2F2\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"v%28t%29=t%5E2%2F2-8t%2B55%2F2\" for \"t%3E=3\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "Graphing this and looking for the next crossing of the x-axis,
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"t=5\"\"s\"\r
\n" ); document.write( "\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "You could also factor,
\n" ); document.write( "\"t%5E2%2F2-8t%2B55%2F2=0\"
\n" ); document.write( "\"t%5E2-16t%2B55=0\"
\n" ); document.write( "\"%28t-5%29%28t-11%29=0\"
\n" ); document.write( "\"t=5\" and \"t=11\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );