document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1081915>Question 1081915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mia could row at 3 times the speed of the water in the river. She could row 16 miles downstream in 2 hours less than it took her to row 14 miles upstream. What was Mia's rowing speed in still water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #695948 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=695948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let r be the rate of the water, and 3r be Mia's rowing speed. Then:<BR>\n" );
document.write( "16/3r+r +2=14/3r-r<BR>\n" );
document.write( "16/4r +2=14/2r<BR>\n" );
document.write( "16+8r=28<BR>\n" );
document.write( "8r=12<BR>\n" );
document.write( "r=12/8=1.5 mph<BR>\n" );
document.write( "3r=4.5 mph is Mia's rowing speed in still water. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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