document.write( "Question 1081891: Recall that for use of a normal distribution as an approximation to the binomial distribution, the conditions np > 5 and nq > 5 must be met. For p = 0.2, compute the minimum sample size needed for use of the normal approximation. Round to the nearest whole number. \n" ); document.write( "
Algebra.Com's Answer #695930 by jim_thompson5910(35256)\"\" \"About 
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Plug p = 0.2 into the first inequality and solve for n\r
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\n" ); document.write( "\n" ); document.write( "\"n%2Ap+%3E+5\"\r
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\n" ); document.write( "\n" ); document.write( "\"n%2A0.2+%3E+5\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28n%2A0.2%29%2F0.2+%3E+5%2F0.2\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+%3E+25\"\r
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\n" ); document.write( "\n" ); document.write( "For the second inequality plug q = 1-p in first, then plug in p = 0.2, and solve for n\r
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\n" ); document.write( "\n" ); document.write( "\"n%2Aq+%3E+5\"\r
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\n" ); document.write( "\n" ); document.write( "\"n%2A%281-p%29+%3E+5\"\r
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\n" ); document.write( "\n" ); document.write( "\"n%2A%281-0.2%29+%3E+5\"\r
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\n" ); document.write( "\n" ); document.write( "\"n%2A0.8+%3E+5\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28n%2A0.8%29%2F0.8+%3E+5%2F0.8\"\r
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\n" ); document.write( "\n" ); document.write( "\"n+%3E+6.25\"\r
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\n" ); document.write( "\n" ); document.write( "Intersecting the two inequalities \"n+%3E+25\" and \"n+%3E+6.25\" leads to just \"n+%3E+25\", as this is the region they both share in common\r
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\n" ); document.write( "\n" ); document.write( "So overall, the solution is \"n+%3E+25\" where n is a positive whole number.\r
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\n" ); document.write( "\n" ); document.write( "We'll need n to be larger than 25 in order to use a normal approximation.\r
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\n" ); document.write( "\n" ); document.write( "The min sample size needed is 26
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