document.write( "Question 1081838: If the terminal Ray of alpha lies in third quadrant and that of Beta lies in first quadrant then the terminal ray of Alpha minus beta lies in......... Quadrant\r
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Algebra.Com's Answer #695893 by jim_thompson5910(35256)\"\" \"About 
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Alpha is quadrant 3 (Q3) so alpha is between 180 degrees and 270 degrees.\r
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\n" ); document.write( "\n" ); document.write( "Beta is quadrant 1 (Q1) so beta is between 0 degrees and 90 degrees.\r
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\n" ); document.write( "\n" ); document.write( "Let gamma = alpha-beta\r
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\n" ); document.write( "\n" ); document.write( "The variable gamma is restricted with this inequality 90 < gamma < 270\r
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\n" ); document.write( "\n" ); document.write( "The lower bound of 90 is from the fact that alpha - beta = 180-90 = 90 (where alpha = 180 and beta = 90)\r
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\n" ); document.write( "\n" ); document.write( "The upper bound of 270 is from the fact that alpha - beta = 270-0 = 270 (where alpha = 270 and beta = 0)\r
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\n" ); document.write( "\n" ); document.write( "So the angle gamma, aka alpha-beta, is located in quadrant 2 or in quadrant 3. \n" ); document.write( "
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