document.write( "Question 95550This question is from textbook algebra and trigonometry
\n" ); document.write( ": WORD PROBLEM : There are 10 women and 8 men in a club. How many diferent committees of 6 each can be selected from the group if equal number of men and women are to be on the committee? PLEASE HELP ME SOLVE!!!! \n" ); document.write( "
Algebra.Com's Answer #69588 by scott8148(6628)\"\" \"About 
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you are selecting groups of 3 from a group of 8 and a group of 10 ... order is not important\r
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\n" ); document.write( "\n" ); document.write( "3 from 8 is (8*7*6)/(3*2*1) ... 56\r
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\n" ); document.write( "\n" ); document.write( "3 from 10 is (10*9*8)/(3*2*1) ... 120\r
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\n" ); document.write( "\n" ); document.write( "any of the groups of men can be combined with any of the groups of women
\n" ); document.write( "so the total number of committees is 56*120 or 6720
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