document.write( "Question 95359: ratio's\r
\n" ); document.write( "\n" ); document.write( "Ancient Greeks thought that the most pleasing shape for a rectangle was one for which the ratio of the length to the width was 8 to 5. If the length of a rectangular painting is 2 ft longer than its width, then for what dimensions would the length and wideth have the golden ratio of 8 to 5.
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Algebra.Com's Answer #69586 by ankor@dixie-net.com(22740)\"\" \"About 
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Ancient Greeks thought that the most pleasing shape for a rectangle was one for which the ratio of the length to the width was 8 to 5. If the length of a rectangular painting is 2 ft longer than its width, then for what dimensions would the length and width have the golden ratio of 8 to 5.
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\n" ); document.write( "Let x = the width
\n" ); document.write( "Then
\n" ); document.write( "(x+2) = the length
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\n" ); document.write( "We want to have the golden ratio
\n" ); document.write( "\"8%2F5\" = \"%28%28x%2B2%29%29%2Fx\"
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\n" ); document.write( "Cross multiply and you have:
\n" ); document.write( "8x = 5(x+2)
\n" ); document.write( "8x = 5x + 10
\n" ); document.write( "8x - 5x = 10
\n" ); document.write( "3x = 10
\n" ); document.write( "x = 10/x
\n" ); document.write( "x = 3.333 ft is the width
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\n" ); document.write( "Length = 3.333 + 2 = 5.333 ft
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\n" ); document.write( "Check our solution, see if it has the golden ratio
\n" ); document.write( "\"5.333%2F3.333\" = 1.6 = 8/5
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