document.write( "Question 1081801: How many ordered pairs of integers (x, y) satisfy y^2 - xy + x = 0? \n" ); document.write( "
Algebra.Com's Answer #695858 by Edwin McCravy(20056)\"\" \"About 
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How many ordered pairs of integers (x, y) satisfy y^2 - xy + x = 0?
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document.write( "\"y%5E2+-+xy+%2B+x\"\"%22%22=%22%22\"\"0\"\r\n" );
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document.write( "Solve for x\r\n" );
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document.write( "\"-xy+%2B+x\"\"%22%22=%22%22\"\"-y%5E2\"\r\n" );
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document.write( "\"xy-x\"\"%22%22=%22%22\"\"y%5E2\"\r\n" );
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document.write( "\"x%28y-1%29\"\"%22%22=%22%22\"\"y%5E2\"\r\n" );
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document.write( "\"x\"\"%22%22=%22%22\"\"y%5E2%2F%28y-1%29\",  \"y%3C%3E1\"\r\n" );
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document.write( "By synthetic division, divide y2+0y+0 by y-1\r\n" );
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document.write( "1 | 1 0 0\r\n" );
document.write( "  |   1 1\r\n" );
document.write( "    1 1 1\r\n" );
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document.write( "\"x=y%5E2%2F%28y%5E%22%22-1%29\"\"%22%22=%22%22\"\"y%2B1%2B1%2F%28y-1%29\"\r\n" );
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document.write( "Since x and y must be integers, so must \"1%2F%28y-1%29\",\r\n" );
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document.write( "and so the denominator y-1 must be 1 or -1.\r\n" );
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document.write( "If the denominator = 1\r\n" );
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document.write( "y-1 = 1\r\n" );
document.write( "  y = 2\r\n" );
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document.write( "\"x=2%5E2%2F%282%5E%22%22-1%29\"\"%22%22=%22%22\"\"4%2F1=4\"\r\n" );
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document.write( "So one ordered pair is (x,y) = (4,2)\r\n" );
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document.write( "If the denominator = -1\r\n" );
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document.write( "y-1 = -1\r\n" );
document.write( "  y = 0\r\n" );
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document.write( "\"x\"\"%22%22=%22%22\"\"0%5E2%2F%280-1%5E%22%22%29\"\"%22%22=%22%22\"\"0%2F%28-1%29=0\"\r\n" );
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document.write( "So the only other ordered pair is (x,y) = (0,0) \r\n" );
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document.write( "So there are two ordered pairs that satisfy the given equation.\r\n" );
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document.write( "Edwin
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