document.write( "Question 95545: Tutor could you please show me how to solve this problem? \r
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document.write( "Rewrite the middle term as a sum of two terms and then factor completely. \r
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document.write( "12w^2 + 19w + 4\r
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document.write( "I can get as far as
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document.write( "a = 12
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document.write( "b = 19
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document.write( "c = 4
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document.write( "mn = 48
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document.write( "m + n = 19
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document.write( "then I get a bit lost. \r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #69583 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 12W^2+19W+4 \n" ); document.write( "THE FACTORS OF 12 ARE 1&12,2&6,3&4 \n" ); document.write( "THE FACTORS OF 4 ARE 1&4,2&2 \n" ); document.write( "NOW FIND A SET OF FACTORS THAT WHEN MULTIPLIED TOGETHER & THEN ADDEDWILL=19. \n" ); document.write( "1*2+12*2=2+24=26 NOT A GOOD CHOICE. \n" ); document.write( "2*6+2*2=12+4=16 NOT A GOOD CHOICE \n" ); document.write( "3*1+4*4=3+16=19 LOOKS LIKE A WINNER. \n" ); document.write( "SO THE MIDDLE TERMS ARE: \n" ); document.write( "(4W+1)(3W+4) \n" ); document.write( " |