document.write( "Question 1081782: evaluate log8 32
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Algebra.Com's Answer #695827 by Alan3354(69443)\"\" \"About 
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evaluate log8 32
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\n" ); document.write( "If the base is 8:
\n" ); document.write( "= log(32)/log(8) = 5/3
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\n" ); document.write( "8 = 2^3
\n" ); document.write( "32 = 2^5
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\n" ); document.write( "\"log%282%5E3%2C2%5E5%29+=+5%2F3\"
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\n" ); document.write( "Or,
\n" ); document.write( "\"log%288%2C32%29+=+log%282%2C32%29%2Flog%282%2C8%29+=+5%2F3\"\r
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