document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1081758>Question 1081758</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangle has sides of length 11 m, 12 m, and 16 m.\r<BR>\n" );
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document.write( "What is the measure of the angle opposite the side that is 16 m long? Round to the nearest degree. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #695782 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=695782\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It helps to draw this<BR>\n" );
document.write( "Law of cosines<BR>\n" );
document.write( "c^2=a^2+b^2-2abcos C<BR>\n" );
document.write( "256=121+144-2*11*12 cos C<BR>\n" );
document.write( "-9=-264 cos C<BR>\n" );
document.write( "cos C=9/264<BR>\n" );
document.write( "take arc cos both sides<BR>\n" );
document.write( "C=88 deg<BR>\n" );
document.write( "should be close to Pythagorean theorem values<BR>\n" );
document.write( "11^2+14^2=265, which is near 256 (16^2). </SPAN>\n" );
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