document.write( "Question 1081734: A simple random sample of size n=15 is obtained from a population with μ=66 and σ=14.\r
\n" ); document.write( "\n" ); document.write( "​(a) What must be true regarding the distribution of the population in order to use the normal model to compute probabilities involving the sample​ mean? Assuming that this condition is​ true, describe the sampling distribution of overbarx.\r
\n" ); document.write( "\n" ); document.write( "​(b) Assuming the normal model can be​ used, determine ​P(overbar x < 69.5​).\r
\n" ); document.write( "\n" ); document.write( "​(c) Assuming the normal model can be​ used, determine ​P(overbar x ≥ 67.6​).
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Algebra.Com's Answer #695780 by Boreal(15235)\"\" \"About 
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the population must be treated as normally distributed or close to it, given that a sample is being taken that is relatively small.
\n" ); document.write( "the sampling distribution is then N~(66, 14/sqrt(10))
\n" ); document.write( "probability mean is < 69.5 in the sample is z<(69.5-66)/(14/sqrt(10))
\n" ); document.write( "=3.5*sqrt(10)/14=0.7906
\n" ); document.write( "probability z < 0.79 is 0.7852
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\n" ); document.write( "z>=(67.6-66)*sqrt(10)/14
\n" ); document.write( "z>0.36
\n" ); document.write( "probability is 0.3594
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