document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1081755>Question 1081755</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Five years ago A age was four times the age of B. Five years hence A age will be the age of B find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #695776 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=695776\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> As the problem is stated there is no solution.<BR>\n" );
document.write( "Five years ago, A's age was 4 times that of B. That makes him older than B.<BR>\n" );
document.write( "Yet, in 5 years A will be the same age that B is now. That makes him younger than B. He can't be both.<BR>\n" );
document.write( "Maybe 5 years ago A's age, *4, was equal to B<BR>\n" );
document.write( "4(A-5)=B<BR>\n" );
document.write( "in 5 years, A's age will equal B's.<BR>\n" );
document.write( "A+5=B<BR>\n" );
document.write( "then 4A-20=A+5, substituting.<BR>\n" );
document.write( "3A=25<BR>\n" );
document.write( "A=8 1/3<BR>\n" );
document.write( "B=13 1/3<BR>\n" );
document.write( "5 years ago, A was 3 1/3, or 13/3.  That is 1/4 th of B's age now.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );