document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1081747>Question 1081747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measure of the arc of a sector is 72 degrees and the area of the sector is 5 pi inches squared what is the radius? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #695771 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=695771\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> area is pi*r^2<BR>\n" );
document.write( "72 degrees is 1/5th of the circle's area, so the entire area of the circle is 25 pi in ^2.  <BR>\n" );
document.write( "That would make the radius 5 inches ANSWER<BR>\n" );
document.write( "the area of the entire circle is 25 pi in^2<BR>\n" );
document.write( "the area of a sector, 1/5th the area, would have an arc of 72 degrees and an area of 5 pi in ^2.<BR>\n" );
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